Hello Ruri, i hope you can help with this question…lets go
When I am able to access the site correctly, sometimes it gives me 2-3 strings of numbers, each string of numbers gives me a different result, I wanted to know if it is possible and do the parse of the 3 strings of numbers, currently I can only do just with the first one, because I don’t know how to take the others and use them.
This is an example of what I get:
Number 1: ": 86778002388
Number 2: “:” 36098254588
Number 3: “:” 21546593265
If i use parse and recursive method, will capture like this:
86778002388, 36098254588, 21546593265
But the request to see the reponse source only accept one sequence number, like this:
https: / xxxxxxxxxxxxxxxxxxxxxxxxx / ? xxxxxx
I’m wondering if it is possible to divide what I capture in the parse and use each separate sequence, like this
This is not valid OB2 syntax $["<pop[*]>"]
The pop variable is already a list if you use recursive mode, why are you trying to make it a list once again?
@Ruri I have a question, lets say I got more than 3 values parsed recursively and I want to implement them in one single request, is that possible?
These are my values for instance: [123, 456, 789, 000]
So I want the request to repeat itself depending on how much values parsed earlier. So in that case I get all the responses from each one using one request only
One request = one response. You cannot have multiple responses from 1 request. You need to use a FOR EACH loop and loop over your parsed values to make 1 request for each of them. Maybe provide some example of what you mean by “one request” if you think I misunderstood you. @AINTHATEASY
So how do I make that possible? I want to use the FOR EACH loop to create requests for example for the three values I parsed but not necessarily always three values it could be four, five or more.
Did you read the post I linked? The problem that is addressed there is exactly the one you are facing right now. You don’t need to know the length of your parsed list, it could be 1000 items and it would still be the same.